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-.8x^2+6x-5.4=0
We add all the numbers together, and all the variables
-0.8x^2+6x-5.4=0
a = -0.8; b = 6; c = -5.4;
Δ = b2-4ac
Δ = 62-4·(-0.8)·(-5.4)
Δ = 18.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{18.72}}{2*-0.8}=\frac{-6-\sqrt{18.72}}{-1.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{18.72}}{2*-0.8}=\frac{-6+\sqrt{18.72}}{-1.6} $
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